my calculus 1 quiz: basic limits (no L'Hospital's Rule)

In this calculus tutorial, I'll be sharing my calculus 1 quiz on basic limits. If you're currently studying calculus or are planning to take a calculus course, you'll want to master the concept of limits early on. In this video, I'll walk you through the quiz questions, explain how to solve them step-by-step, and share some tips on how to approach basic limits. Whether you're struggling with limits or just looking for a refresher, this video is for you. So sit back, grab your pencil and paper, and let's dive into the world of calculus limits! Don't forget to like and subscribe to @bprpcalculusbasics for more math-related content.

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[bprpcalculusbasics]

Could someone please do the timestamps? Thank you very much!

[mycry]

Amazing help for my calc exam just in time, thanks man

[theletter]

9:27 You don't need derivatives or numerical approach

let y=x^4-1
so x=(y-1)^1/4
we must change our limit as well to 0 to reflect the change in variables

We the have
lim y-->0
1/4ln( y+1)/y
factor out the 1/4 from our limit since it a constant

(We then use the log division property)

ln((y+1)^(1/y))



(y+1)^(1/y)

As y goes to zero well this one of the definitions of e

so we now have 1/4 ln(e).So overall 1/4

[Nathangamer-qkly]

wow nice video I'm really a huge fan of math

[teamzumali]

for Q4 i changed the variable, I let x=3+h and the limit is also 1, is it correct ?