Logarithm Class 11 | One Shot | JEE Main & Advanced | Arvind Kalia Sir

Best Logarithm One shot session for JEE by Arvind Kalia Sir
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The teaching style of Arvind Kalia Sir is known for his clarity, concise explanations, and ability to make complex concepts accessible to students.

In this one-shot video, Arvind Kalia Sir covers the topic of logarithms, which is an essential concept in mathematics and plays a significant role in mathematics. The video aims to simplify the complex concepts related to logarithms and make them easily understandable for the students.

This session aims to provide Class 11 students with a solid foundation in logarithms and equip them with the necessary knowledge and problem-solving skills required to excel in the JEE Main and Advanced.

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Timestamps
00:00 - Introduction
01:50 - Nature of Chapter
04:35 - Basics of Logarithms
16:02 - Properties of Logarithms (Part 1)
01:06:40 - Properties of Logarithms (Part 2)

#jee2025 #jeemain2025 #jeeadvanced #jeeadvanced2025 #unacademy #jeenexus #arvindkaliasir #onlineclasses #jeemaths

[harshrajjha]

For all those who didn't understand how sir isolated x at 40:15

We have,

x•log3 = (x-1)•log4
x•log3 = x•log4 - log4 (Distributing log4)

x•log3 - x•log4 = -log4
(Subtracting x•log4 from both sides)

-x(log4-log3) = - log4
(Taking x common)

-x = (-log4)/(log4-log3)
(Dividing both sides by log4-log3)

x = (log4)/(log4-log3)
(Multiplying both sides by -1)
Hope it helps.

[kronpuff]

1:45:00 there should be root 3 instead of root 2 in case anyone need help not pointing out the mistake

[Future_iitian_]

1:25:51 for those students who were not able to do
Log b/log a^n = let base be be a^n
Then log a^n b / 1
So log a^n b
Now by second deduction
1/log b a^n
1/n * 1/log b a
1/n * log a b

[khushihirwani]

40:14
xloga3=(x-1)loga4
xloga3=xloga4-loga4
xloga3-xloga4=-loga4
-x(loga4-loga3)=-loga4
x=loga4/(loga4-loga3)

[zebra]

he is looking more young in Unacadeny Vs Vedantu 😊All the best

[studyboy]

Timestamps
00:00 - Introduction
01:50 - Nature of Chapter
04:35 - Basics of Logarithms
20:05 - Properties of Logarithms (Part 1)
01:11:05 - Properties of Logarithms (Part 2)

[suhanisahay]

We love you sir ❤ thank you, aapse best teacher maths ke liye aaj tk koi nhi mila, aap best ho 💛

[educatewithkabir]

Thankyou jee nexus by unacademy and arvind sir for giving amazing content .My concept about logarithm has become clear❤❤

[prateekshrivastava]

I am not a JEE aspirant I just saw this video and watched it, and it took me 5 days to understand it completely. Thank you so much Sir you explained everything nicely

POV( Not an JEE aspirant please don't judge me that I took 3 days to understand it I am just an average student )

[radhashyamsundar_]

hare krsna bhai

everyone knows maths is the most toughest subject in JEE aapke one shots bhot help kr rhe hai 11th backlog ke liye bas ek request hai ki please please please one shot ki vjh se lecture chota mt rkho chahe 1-2 hours extra extend krdo video lekin ekdum advance level tk ques practice krwa do jee valo ne maths ka level bhot bdha diya hai please usko dhyan me rkhte hue one shots do 8 hrs tk ke one shots bhi de do ham pdh lenge bas high level ques krwao advance level tk

[vikram_singh]

Aap thodi unacademy ki t shirt mein different lagte ho but dheere dheere is t shirt se bhi feelings connect ho jayengi

[aspirant]

59:36 You can't take log3 base x as t when you have already assigned it the value x= logx base a

[Saad-bh]

Baap re baap kya heavy padha rhe hai sir...Dil dimmag sb khul gaya..Majaa aa gaya....Sir aap problem solving sessions Lao na plz..Ye 11th aur 12 th ke concepts Mila ke...

[ishanaryan]

1 like = 1 less 8-9th student yapping in the comments

[prarthanadubey-vphd]

1:46:12 it should be root 3 not root 2

[.ch.tanishq]

57:23 Sir why is the answer wrong when done like this:
X^(log x^2+(log x)^2-10)=x^-2
log x^2+(log x)^2-10=-2
Let log x be a
a^2+2a-8=0
And after solving this we get a=-4, 2
And from here x is 9 and 1/81

[GamingMB]

50:58 Sir maine alag approach lagayi
First i converter log27 to the base 3 in 3log3 to the base 3...
then log3 to the base 3 becomes 1 and 2 + 3 = 5 then finally i converted logarithmic equation to exponential and it became

3^5=(4x+7)

[ramakarandikar]

I think you are the best maths teacher now on yt

[Khushwant-lzjn]

Surprisingly this lecture is not boring at all😊

[ParthManchanda]

1:06:04 we could also take a fraction of all (two equations at a time) then calculate p and r in form of q and compare to any one of the equations and calculate p, q, r