Propositional Logic (Solved Problem 2)

Discrete Mathematics: Propositional Logic (Solved Problem 2)
Topics discussed:
1. Solution of GATE-2008 question based on propositional logic.

Music:
Axol x Alex Skrindo - You [NCS Release]

#DiscreteMathematicsByNeso #DiscreteMaths #PropositionalLogic

[vovanmilos]

Thanks to your previous lessons I already had solved this one by myself, just checked the answer in the end.

[lalitverma]

Wow nice question thnx to give solution sir ..Iam prepareing for gate cse

[amitpal]

if we try to solve it using T and F method, then the answer will be (D)All of these
lets assume p and Q both T
1. P or ~Q = T or F = T
2.~(~P^Q) = ~(F^T) = ~F = T
3. (P and Q) or (P and Negation of Q) or (negation of P and negation of Q) = (T and T) or (T and F) or (F and F) = T or F or F= T or F = T
4. (P and Q) or (P and Negation of Q) or (negation of P and Q) = (T and T) or (T and F) or (F and T) = T or F or F= T or F = T

[advaithkumar]

actually we didn't need to even check 4th since its obvious it cant be equivalent to 1, 2, 3

[kirekav]

where u have ' in the propositio ?? you make a big trouble you dont need to do that
if you know you know, but here is the people who wanna learn. why use simplicity or some s*** in the exam?

[kirekav]

if you write this on exam like here you never pass the exam because its not alowed to make your private math in discrete math .

[KeshariPiyush]

You made a mistake while copying 4th proposition. Answer should be all of them are equivalent.