Calculating a Fourier series for a periodic step function

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In this video, I calculate the Fourier coefficients for the Fourier series of a periodic function with jumps in it.
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why did you put a limit -1/2 to 1/2 instead of 0 to 1? if it is not a step function we just put f(x)=1 or something but how do we put value for f(x) if it was a step function? (for final answer )

kumuduninilanthi
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what if instead of a -1 the function was actually =0 between 0 and 1/2?? please help

NMelvynN
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You should be changing n to (2m-1) to account for the fact that even integers of n zero it out shouldn't you?

mysteriousmufman
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At around 1:30, you could have integrated from -1/2 to 0, and plugged in +1 for your f(x), correct? Just making sure I understand. Great vid!

gilbert