Algebra I #3.9c, Proportions - Means and extremes

An explanation of the parts of a proportional equation, the means and the extremes, and how to use the Multiplication Property of Equality to solve for an unknown variable. Also, how to solve it by using division. #3.9c

Algebra I #3.9b
Proportions - Cross multiply and Cross products

Algebra I #3.9a,
Ratio vs Proportion

Grade 8 Math #3.1a,
Proportional relationships with tables

Grade * Math #3.1b,
Proportional relationships with equations

Grade 8 Math #3.1c,
Proportional relationships with graphs

Grade 7 Math #4.2a,
Proportions and rate of change

Grade 6 Math #5.3,
Proportions - proportional fractions

Grade 6 Math #5.4,
Solve Proportions using equivalent ratios

Grade 6 Math #5.5,
Solve proportions using unit rates

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[shreyamohinta]

Thank you so much! Your explanation is brilliant! My maths test is day after tomorrow and I wasn’t able to understand the concept. However, after watching this video, I understood it really well! 😊

[tomfrantz]

My 60 year old Geico-man brain is slowly getting it. The Means are close to each other in the equation, the means are X-variable and either arranged to be preferably driven by the numerator as in this video—or in the denominator brackets and cross multiplied as a mean and turned into a coefficient with a variable attached such as "9X" and then plugged in above the extreme below it or above it, and a proportion is derived by using division to "dissect as it were" a proportion showing a miracle of (9X equals 36) and then you take 9X and divide it over 36 to get thirty six—ninths or a new product called, "4 over 1" by reducing the equation—creating a newly defined mean called X=4. So in summation by arranging a coefficient with a temporary new variable and diving by the old comparative numerator or denominator you get a new proportion that has to be re-written to define the "New and improved" arrangement of (9x/36) EG (36 divided by 9 equals four over one) Plug that in and you get an actual alive and well reformed variable with an actual product for comparative analysis.

[lovechants]

Thank you I’ve been struggling in a lot of my classes especially math and my anxiety makes it worse

[ramdemesa]

Tnx for video I appreciate it math is my bane

[mnpearls]

How do you determine which number or fraction is coefficient?