Linear Equation of Order One (2ycosx + sin⁴x)dx - sinxdy = 0; when x=(𝝅/2), y=1

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Solving (2ycosx + sin⁴x)dx - sinxdy = 0; when x=(𝝅/2), y=1 using linear equations of order one.

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  1. TheAppliedPhysicist
  2. (2ycosx sin^4x)dx
  3. 2ycosx
  4. (2ycosx sin^4x)dx sinxdy=0
  5. sinxdy=0
  6. Linear Equation of Order One
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