Lecture 1.2 - Conjugation and Absolute value

Conjugation and Absolute value

[jtchavda]

At 13:24
By defining 0^0 = 1 Then 0^n+1 = (0^n)●0
will make problem
We should say 0^0 is not defined

[stevilimfax]

relation on 23:09 is not true at all because N(z)=a^2 + b^2 and N(z conjugate)= a^2 - b^2 - 2abi, nevertheless great lessons!