Advance Illustrations – Sliding Over a Prism | Newton's Laws of Motion #19 for JEE Advanced

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Questions asked in JEE Advanced are based on critical thought processes rather than direct application of concepts. For preparation of JEE Advanced, students have to focus on problems based on multi concept applications.

Ashish Arora Sir has taken up a case of Sliding Over a Prism which is important for select in IIT.

Watch Advanced Illustrations Kinematics videos on various concepts:

#jeeadvance #jeephysics #pg4AdvIllustrations #nlm4jee #newtonlawsofmotion
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so basically the secret lies in drawing fbd :)

yadavshashankkumar
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We have to take a lot of care in solving these questions....they're simple but there are so many forces that we always miss something

CristianoRonaldo-jj
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Sir I did most of all your advanced illustrations on my own, I am revising for jee adv 2020(whenever takes place ) and this is my 2 nd time revision of these after 6 months, hopes are high, and your blessings are required sir...

tilakrajnarang
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hmm nice illustration, fortunately solved it on my own.

kuldeep
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Koi yaha aaya kya mai 8 saal baad aaya hu... Jee 2023

physics
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sir as mass of prism is m1 so pseudo force should be m1a1. Sir, if I am wrong here pls correct me.

ishankhandelwal
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I want to check this comment after I clear iitjee

sailendranagakumar
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Sir, because no external force is acting on the system then Acceleration of Center of Mass must be zero for which the sum of accelerations of the system must be zero.... How can we use this method to get the required result...

satviksharma
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Excuse me sir, why did you consider (mu)N2 in case of How the friction act up and down as well.Thank you sir..

VinayKumar-nruv
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Denominator mein sirf m1 m2 nahi hoga kya..?

integratedone
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I did it in the first attempt!!!! yippie😁😁😁😁😁

vijayvyas
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2:30 can anyone here explain me this why here it is better to consider under pseudo frame

ashishmittal
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shouldn't we get a + instead of - in the denominator? rest is fine

k.ashvanth
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sir at 5:10 in eq 3 why negative it should be +ve

lionon
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Sir in this question can i say a2=a1cos@

arunteltia
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sir i am having trouble solving these equations formed having sin and cos terms and eliminating variables

brijamohanju
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sir how did the alpha came b/n N2 and m1g in and of A????

alpadesai
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Sir, can we solve this problem by taking A+B together as a system, and since friction is acting on both of them, net force along horizontal direction is zero, and hence accn of A should be equal and opposite to that of B, as COM should be at rest?

chennakeshava