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Proof: Derivative of sin(x) = cos(x) by First Principles
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In this video, we prove that the derivative of sin(x) equals cos(x) by the very definition of the derivative, which is:
df/dx = f'(x) = lim_(h approaches 0) f(x + h) - f(x) / h
Thus:
d/dx [sin(x)] = lim_(h approaches 0) sin(x + h) - sin(x) / h
Thanks for watching. Please give me a "thumbs up" if you have found this video helpful.
Please ask me a maths question by commenting below and I will try to help you in future videos.
df/dx = f'(x) = lim_(h approaches 0) f(x + h) - f(x) / h
Thus:
d/dx [sin(x)] = lim_(h approaches 0) sin(x + h) - sin(x) / h
Thanks for watching. Please give me a "thumbs up" if you have found this video helpful.
Please ask me a maths question by commenting below and I will try to help you in future videos.
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