'Calculus Is EASIER Than PreCalc'

Do Science And Math Classes Get Easier? Harder? Or Stay The Same As You Make Progress?! #Physics #Chemistry #Math #ScienceIsFun #NicholasGKK #Shorts

[dtvtcmb]

Calculus concepts are far more down to earth. Understanding anything about derivatives was easier that idk, polar functions.

[architech]

I still think calculus was easier to absorb and retain than precalculus

[Obecox]

The study of pre-calculus involves the application of various mathematical formulas. Calculus, on the other hand, focuses on determining the slope of a curve and calculating the area under a curve.

[imagod]

For anyone curious about the bottom problem, the solution is 0

[Garfield_Minecraft]

That's why I'm bad at arithmetic but did well on set theory and calculus

[SuperSyntax-sw]

Amazing distinction to make, well designed video

[MrYellowAndYacello]

Though I don't have experience in calculus yet, I want to know the solution and how to calculate the bottom expressions.

[Puppeteer_in_the_Void]

I've noticed that honors math classes are less tedious than regular math classes of the same grade and subject

[ComposedBySam]

Idk… I would solve the bottom problem tbh

[cyborgvison]

So now, correct me if im wrong, havent done any sort of calculus in a year or so, but cant you do f prime, get rid of the integral so f'(y)=g(x) plug in g(x) then take the derivative 9 more times? I know the answer is 0, but cantyou do that?

[ForsakenedMilk]

So hear me out; What if they just had one bad precalc teacher and then an amazing calculus teacher. From school to school, it’s different.

[SarahTheAmbiguous]

If you pretend like integrals don't exist, for me precalc was harder than calculus. However, and I have no idea why, I just absolutely suck at integrals, and no matter how much practice I get with them I still need help choosing which strategy to use. The strategies themselves are easy for the most part (integration by parts 3 times in a row is everyone's favorite thing) but I never know how to set them up or which ones to use

[TreyWilliamson-kubi]

The other consideration here is the difficulty jumps between levels of math. For many people, going from high school algebra/geometry to the trigonometry, college algebra, complex numbers, polar coordinates, etc. found in precalculus is a greater increase in difficulty than the jump from precalculus to the derivative rules and simple integration in calculus I. The material is still harder, and the concepts from precalc were necessary to understand the new material, but you might find yourself struggling less with Calc I, for this reason.

[lamalamalex]

As one of those students. Nothing before calculus made sense to me. Yet calculus solved everything for me.

[its_puggy_pugster]

Yeehah!! Algebra and calculus in one video!? What is it, my birthday?? 😜

[CalistoArc]

Okay Im biased because I am a decent calc student but like I still would argue that problem 2 is easier. I think tedium and difficult are two different things but I also think that when people go into calculus they are expecting it to be plug and chug or which formula do I use. Which I would argue is more so an issue with the way math is taught. (This opinion will definitely be unpopular)

[sharingheart]

I disagree. Calculus 1 is far easier than pre-calculus. I mean, the rules for basic derivatives are a lot easier to remember than the quadratic formula as is. You could easily teach Calculus 1 before college algebra. It won't make as much sense, but people would still ace it far more often than college algebra.

I still remember the first thing I was taught in calculus 1: "A line without a break in it is called a continuous line. If it has a break in it, it's called a non-continuous line." The professor even showed drawings and went into detail.

Calculus 2, however, is a very cruel reminder for why some people have to choose between STEM subjects and good mental health.

[KotikKelTuzada]

It took me 11 seconds to solve bottom one... Ig I don't good enough(

[lucalal]

Solution of f^{(10)}(y) :

f^{(10)}(y)=\int_{0}^{y} x^{8}-126dx

By integrating, we get the antiderivative of g expressed in y, so f^{(1)}(y) is simply y^{8}-126
By derivating again, we get 8y^{7}

Since f^{(2)}(y)=8y^{7}, we see that x is at the power of 7, so 7 derivatives later we will get a constant that i'll name "a", so we get:

f^{2+7}(y)=a
f^{9}(y)=a
f^{10}(y)=0

[DaFeMaiden]

I’m sorry hands down calc 3 is way easier than calc 2. Maybe you could argue the jump in difficulty is way higher for calc 2. Everyone I’ve asked agrees