How to Sum of the First N Positive Integers in Python

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Комментарии
Автор

I used my logic and I got this different code with same results :

N = int(input("N = "))
sum = N
for n in range(1, N):
sum += (N - n)
print("sum =", sum)

the code work like this:
sum=N+(N-1)+(N-2)+...+(N-N)
if N=3 then
sum= 3 + (3-1) + (3-2) + (3-3) = 3+2+1+0 = 6

Era_Of_Awakening
Автор

I think i should wach this, it really nice, thanks for your videos ! Keep going !

tahaanass
Автор

n=int(input('enter the numbers'))
i=1
sum=0
for i in range(n):
sum=sum+n
n=n-1
print(sum)

junaiddooast
Автор

n = int(input())
sum = 0
for x in range(1, n+1):
sum+=x
print(sum)

codexcodexcodex
Автор

You mentioned N positive numbers and so the below code takes N inputs and calculates only the positive numbers:

usr_input = int(input("How many positive integers do you want to calculate the sum for: "))
total_sum = 0

for i in range(usr_input):
num = int(input(f"Enter positive integer {i+1}: "))
if num > 0:
total_sum += num

print(total_sum)

LearningBigdata
Автор

def sum_till_numbers(num):
sum = 0
if type(num) == int:
for i in range(num+1):
sum = sum + i

return sum

else:
return ("given arg is not int")


print(sum_till_numbers(8))

GAURAVSINGH-ezoe
Автор

user_x=list(map(int, input('enter list of numbers:').split()))
positive_x= [num for num in user_x if num > 0]
print (sum(positive_x))

jananelalouani
Автор

n*(n+1)/2 also works, order of precedence

AlexandrBorschchev
Автор

num=int(input("Enter the value of N "))
print("Sum is", (num*(num+1))/2)

dipakkandel
Автор

#sum of positive numbers
num=int(input('enter the number : '))
answer=0
for x in range(num+1):
answer+=x
print(answer)

manojkumarm
Автор

n1 = 5
i = 1
sum = 0
while i <= n1 :
sum += i
i += 1
print ("total sum is ", sum)


is this right, ignore the input

Atharva_op
Автор

Why are we using n*(n+1)/2? Can anyone explain me little 🥺

rameshm
Автор

The title seems to be off putting, why is the title is this? The program seems to do different thing

Eeatch
Автор

class Prac:
total = 0
def __init__(self):
self.n = int(input("Enter number : "))

def avg_num(self):
sum = self.n*(self.n+1)/2
return sum
while True:
av = Prac()
if av.n<=10000:
print(av.avg_num())
else:
print("Enter number less then 10000\n")
continue

anubhavsingh