Partial Fractions: Quadratic Factor

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Simple example separating a fraction into 2 fractions, one linear & one quadratic factor in the denominator, equating coefficients
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Thanks a lot Jay. I loved it!! You've helped me to solve my misconception.

williamlee
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Thank you for choosing to solve the hard types

gabrielremilekun
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1:36 if the highest power of x in the numerator is the same as that in the denominator, would the fraction become improper? Having some trouble understanding how there can be no constant if highest power is x, your help is greatly appreciated!

limxinhuibbss
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Crystal clear jay! Thank you. You made it easier 🤍

zuhanisthar
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Thank you Ma'am. It was life-saving

nurzahanmukta
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Hi Jay,
We love the content and think you are a great teacher. We are a relatively new maths channel and any tips on how we could improve our content would be much appreciated

sbmathsyt
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The last part where u had 7=A+C got me confused. Why did u pick just the coefficient of x^2 and A+C leaving the other terms?

ipuoleanthony
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Hello thanks for the video. But why did we use x= -1 & x=0 ?

davelaguerre
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should we factorise x^2-3 into (x+sqrt3)(x-sqrt3) first?

chongweechan
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7x^2 + 3x - 14 / (x^2-3)(x+1) aren’t the highest degree of powers in both the numerator and denominator
= 3 , on each side?

zahraahsan
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Hello Jay, please can u stream more like this problem. For ex, make L the subject : L^~64L/2xy+8= cube root (L^-64)^\square root (Lxy+4)^ . Can u help please?

fluffycats
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Sir
Px+q/(s+1) (s+1)
What will be the form
Pls replay 🙏

വാളയാര്പരമശിവം-ധട
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I'm still confused with how you got A=2 😕

beniditolevu