PROOF OF ELECTROSTATIC SHIELDING AND EXISTENCE AND UNIQUENESS THEOREMS

LUCID EXPLANATION AND PROOF OF ELECTROSTATIC SHIELDING AND EXISTENCE AND UNIQUENESS THEOREMS. REMOVES COMMON MISCONCEPTIONS ABOUT SHIELDING

[daveshammgod]

Brilliant!! Sir you're awesome.
You cleared all my doubts, I don't know how to thank you sir!😃😃

[kingpatil]

The wait of videos is worth. Thanks a lot sir 👌🏻

[mihirkaskhedikar]

Nice concept, especially the simple proof of uniqueness theorem👍

[sainavaneetmukund]

Sir I really liked the video but as a humble request, will you please continue your series of original problems

[sushenpaidipaty]

Highly intuitive and sweet explanation. Loved the video. Question in the end was cherry on the cake. Superb as always sir . Great respect 🙏 👍👏👌😀

[yakaiahbandari]

that pathfinder problem ..was done ..in 10sec ..:)

[sakshamarora]

thanks a lot, sir for this video, the proofs were quite convincing.My concepts are much better now

[vedarthbhawsar]

Sir, please upload video..
It is very helpful ..

[vibhanshuvaibhav]

Thank You Sir. This video was really helpful! :)

[xyz]

Sir why you stoped producing these types of super videos??


Plz continue this, we need it a lot

[mipa]

sir one doubt!....sir the contradiction used in question, undermines the statement of theorem in the sense that statement mei likha hai ki given configuration of universe and of conductor, but in contradiction we are changing the configuration of charge and of universe. am i missing something sir?

[dipayandas]

@24:18 sir why is potential due to the inner charges on the outer surface 0 ....if the inner pair are producing 0 field outside that would mean the potential on the inner surface due to the inner charges must be equal to the potential by them everywhere outside ... How can we prove that potential due to them is 0?

[evolvebatchexclusive]

i remember this problem : nitin sir made us do this in class !

[rounitkamal]

In the proof of claim 1, when you are decreasing the size of the hollow conductor from infinite to finite, why did you ignore the presence of a charge density on the outer surface of the conductor, like even if I remove the top layer of charges, a new layer of charges will appear on the outside. And as the conductor becomes finite this charge layer will provide a significant electric field inside the metal.