Why charges reside on surface of conductors | Electrostatic potential & capacitance | Khan Academy

Why do charges reside on the surface of a conductor? Because that's the only way the electric field inside the conductor can be zero. Let's explore the electrostatics of conductors in detail.

Khan Academy is a nonprofit organization with the mission of providing a free, world-class education for anyone, anywhere. We offer quizzes, questions, instructional videos, and articles on a range of academic subjects, including math, biology, chemistry, physics, history, economics, finance, grammar, preschool learning, and more. We provide teachers with tools and data so they can help their students develop the skills, habits, and mindsets for success in school and beyond. Khan Academy has been translated into dozens of languages, and 15 million people around the globe learn on Khan Academy every month. As a 501(c)(3) nonprofit organization, we would love your help!

Created by Mahesh Shenoy

[Lets_crack_it]

yesterday I was asking to my sis this question and today u uploaded this video. I m shocked. love u❤

[gouravmishra]

these videos really create an impact in developing our concepts in physics...

[yuvrajtiwarybitmesraece]

Hats off to you sir well explained👍👍👌👌

[taniwha]

Nicely explained and I like how excited you sound

[seemafalak]

Ram Sir, shouldn't the charges be present on the inner surface as far apart from each other rather than being completely outside the metallic ring ? How do we get the excess charge on the outside?

[hoschi]

I think the explanation with Gauß is wrong because the E field in Gauß is from the inner Charges only. Its Not the Total electric field. For the Total field you should add the field coming from the outer Ring Charges. The Total field at a point should be Zero but the E field in Gauß law is NOT the Total field. Thats my point.

[pascale]

Thank you for the wonderful explanation! :D

[ayshaazath]

Thanks alot sir.what a great explanation

[yash]

8:10 "but what if it wasnt a uniform surface" - ohh yes, i read in the introductory material, that in those cases, the charge distribution is inversely proportion to radius. am i right?

[jameslimary]

Do we agree that this is only valid assuming all moving charges have the same sign? Else I'm missing something out)

[jeonsday]

in the second case shouldn't the metallic surface right outside the cavity act like a shield? which would make it seem like no charge is enclosed by the metal

[jesussaquin]

is it because the electric field lines entering the object are the same leaving the object?

[hassanjafari]

At the beginning of the video you are saying that positive charges start moving... This is a contradiction which we all know positive charges do not move. May you explain it to us please?