Applying Quotient Rule To A Problem (Simplifying The Quotient Rule Formula) | Jake's Math Lessons

Applying Quotient Rule To A Problem (Simplifying The Quotient Rule Formula) | Jake's Math Lessons
Applying Quotient Rule To A Problem (Simplifying The Quotient Rule Formula) | Jake's Math Lessons

Recently in one of my weekly live streams which I do every Monday night at five o'clock pacific time I talked about quotient rule. And I broke down the quotient rule formula to make it nice and simple. In this video I wanted to go back and show you one of the examples I did in that live stream. So that's what this video is going to be about. Be sure to stick around at the end of the video and by the end you'll be feeling a lot better about quotient rule and how to apply it on your own so that you can boost your scores and do well on all your exams.
And just a quick reminder, Quotient rule is one of the topics covered on my calculus one study guide and my complete calculus one package. If you want to check that out there is links down in the description and the pin comment below where you can learn more about both those things. They are both available for instant download so you can start using them right away.
Anyway, without further due let's go ahead and jump into this example and I'll show you how you can apply the quotient rule and hopefully make you an expert by the end of this video.

The Problem which I am discussing ,
Use the quotient rule to find the derivative
y = (x+1)/(x^3 + x -2)

Chapters,
0:00 Introduction
0:55 The problem
1:10 The quotient rule formula
1:30 Figuring out high & low
2:20 Finding derivatives of high and low
3:05 Plugging the values in the formula
3:46 Simplification
8:15 Solve for the problem
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Some links in this video description may be affiliate links meaning I would get a small commission for your purchase at no additional cost to you.

Your Queries,
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#jakes_math_lesson #quotient_rule_formula

[JakesMathLessons]

0:00 Introduction
0:55 The problem
1:10 The quotient rule formula
1:30 Figuring out high & low
2:20 Finding derivatives of high and low
3:05 Plugging the values in the formula
3:46 Simplification
8:15 Solve for the problem