Conditional Probability Distributions With Solved Examples & Exercise || Tutorial 4 (C)

This video is a prerequisite video to assist learners in joint probability distributions and stochastic processes. This video describes conditional probability distributions for both discrete and continuous cases with examples and exercises.

Solution : 1. (a) m = 1 and n = 1 (b) e^(-2) = 0.1353
2. P(Y=y | X=x) = (x+2y)/3(x+2) and P(X=x | Y=y) = x+2y/3(1+2y)

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