Solve the Exponential Equation e^(x + ln(3)) = 4e^x

Solve the Exponential Equation e^(x + ln(3)) = 4e^x

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[ryanalnaser]

whatever anything now or after or did or do or anything

[martinnolin]

So: x = Ø
When you log a function you add a tau term at the end (+ τin) but that doesn't change things since e^τin is 1

[rdabek]

What about 3*e^x = 4*e^x => 0 = e^x*(1-3/4) => e^x = 0 => e^x never reaches zero but in a limit x would need to be -inf, am I thinking right?

[az_t]

i did my try and i get e^x = 0 so x = -infinity