Solving An Amazing Exponential Equation | Can You Try?

Solving An Amazing Exponential Equation | Can You Try?

Welcome to another interesting algebra challenge! In this video, we'll be solving an exciting exponential equation that will test problem-solving skills. Whether you're preparing for a Math Olympiad or just love a math puzzle, this problem is perfect for you. Grab your pencil and paper, and let's see if you can solve this exponential challenge!

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[robyzr]

Dear teacher, just a question pls :I used the same method, but I considered the quantity (a+1/a) > 0 always, and so when obtain the solution negative (a+1/a = - 1) not calculate more as you did, but rejected right away that solution. Is it correct.?
Thx a lot 😊

[Quest]

2^1lx= (3+-√5)/2 or
X=1/[ log_2 (3+-√5)/2]

[RealQinnMalloryu]

(16x)^ ➖ (4x)^2+{1x+1x ➖ }/{8x+8x ➖ }+{2x+2x ➖ }={256x^2 ➖ 16x^2}+2x^2/{16x^2+4x^2}= 11^11x^1^1 11^1^11^1x 1^1^1^1x 1^1x (x ➖ 1x+1).

[Fjfurufjdfjd]

Θετω 2^(1/χ)=α>0 και εχω α^4-α^2+1=2α^3+2α; α^4-2α^3-α^2-2α+1=0 ; (α^2-3α+1)(α^2+α+1)=0 στο δευτερο τριωνυμο ειναι Δ=-3<0. Αρα