Arithmetic and Geometric Progression Part 1 (AP and GP) | Sequences and Series | Class 10 Maths

Arithmetic and Geometric Progression
AP and GP
Class 10 Maths
ICSE CBSE NCERT

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[abasednerd]

21:53 A slight correction:- 18+15=33. And, 52-33= 19. So the answer is 4th term= 19.

[sathviknalawade]

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[iitd]

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[nityashukla]

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Thank you very much sir

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Like those who want 3x button for speed 😅

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[adityaprasad]

In question 4 if last term and d is given you can easily apply { l-(n-1)d}

[margaretmenezes]

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[destroygamer]

Sir in 21:42 the addition's answer will be 33

[Chizuru_Yukimura]

Sir you are an amazing teacher, I recently came across your channel and now refer to only your videos. Thankyou for your efforts!

Sir for Q4, there is an easier method by using the formula :-
9th term from end= L- (n-1)d
185-(9-1)4
185-32= 153

[mukti]

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[khetalshende]

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[kattarsanatanigaurvanvithi]

In taking out 9th term from end.
Simply last the last term as 'a'and then,
an = 185 - (n-1)d.
an = 185 - (9-1)4.
an = 185 - (8)4.
an = 185 - 32.
an = 153.
So, you got your answer i.e. 9th term from end is 153.

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[anilpandey]

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[sixthsense]

Sir Q)5th ka Answer 19 hoga
Bahut acha smjhaya

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[asishmukherjee]

The solution for the following problem could have been solved easily by using formula as I am showing
Q. Find the 9th term from the end of AP
Solution: L -(n - 1 )d.
185 - (8)4 =153 Ans.

[aaditya_aspirant]

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