Calculus - Continuous functions

[lowellrublico]

In the question "Where is the function continuous?", the answer for this also answers the same question "What is the domain of the function?"

[ishaj]

I have my exams today nd watching this video right before was worth, much clear now. Thank you so much sir

[AgravatVishal]

Method of glass board and different colourfull markers is amazing 😘
And totally understandable knowledge.

[adminassistant]

"Up to 1 and from 1 to infinity"....isn't that implying that 1 is ok to use, which would make our function DNE?

[bramvandewalle]

Wouldn't it be easier to say that sin(2x)=0 <=> 2x = k(pi) <=> x = [k(pi)]/2 and k is element of Z (integer)?

[prescottluah]

Sir, humble suggestion that you can list all D.N.E., where, x = 0 + n(pi/2), which n b.t.n. any of Integer-numbers

[lakkojisantoshkumar]

can I know the continuity existence of a function x^(1/3) at [-1, 1]

[huzaifa-pcoc]

What if the function f(0)=0 ? Is it Continuous there?

[romanrks]

sir, have you any class about the continuity of the vector function?

[gamutiachannel]

How to solve this? h(x) = x-2/(x+1)(x-2), a=-1

[dpmike]

I am confused.  If a function is differentiable then the function must be continuous on the domain of the function.  Then why is the f(x) = (x^2 - 4) / (x + 2) differentiable when    x cannot equal -2, which means there is a hole in the graph at -2 making it non-continuous.

[Retrfr]

This is the worst vid for explanation
You hardly explained how to find out if it's continuous or not

[InLeoWeTrust]

Am I the only who thought of Mean Girls every time he said "The limit does not exist"? 😂

[charliesymon]

at 4:27 should the interval be (-infinity, -4)U(-4, 3] instead of (-infinity, -4)U(-4, 3) since 3 exists and is continuous?

[nicolewade]

Why are we including -4 if there is a hole there? Please help :, )