Continuous, Discontinuous, and Piecewise Functions

We know a lot about functions now, so let's look at some special cases where functions get weird and jump around.

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[yogeshdharshan]

Your intro song was soo funny, it's like retro cartoon song

[rik]

Your intro and outro reminds me of some old educational cartoon I use to watch when I didn't go to school as a child. I love that vibe

[amjadhossain]

You are one of the best mathematics teachers l have seen ever. Your videos are too helpful for the students like us.We get immense help from your videos.These videos make our topics quite easier.Carry on.

[PeakOfPeace]

There is a lot of intensity in your voice, your words directly go into my head.😄

[Alpha-bzke]

Great tutorial. I completely understood continuous and discontinuous with just one explanation.

[tino_]

MR PROFESSOR DAVE THANK YOU SO MUCH I DONT KNOW WHAT I WOULDVE DONE IF IT WERENT FOR YOU THANK YOU AGAIN <3333

[mansanasmdelf]

Thabk you so much!!! This helps me a lot

[mubeenkhan]

Sir please make a lecture on how a discontinuous function is converted into a continuous function with the use of unit step function.

[leetoka]

Thank you professor dave! Liked and subbed

[nikocvitanic]

bro that's about as simple as it gets. you're a fucgggging G

[AlessandroZir]

thank you!! very clear and intuitive; you do know how to teach;

[CartoonKidOLLY]

3:05 that was totally you scratching your beard

[ThWRizzler]

W you remind me of my younger days in elementary school but for harder math!

[psstudycentre]

Superb sir... I understood in a easy way.. 😇

[anmolkotiyal]

The way he Explains.... Like puts effort in his I get it Totally.... Humble guy 😄

[pranavsblog]

Your a great teacher amazing exmalantion

[physics_enthusiast_Soorya]

Any function with a vertical asymptote must be a "Continuous" function, according to my textbooks..

My teacher told me that they will never meet, but that doesn't mean there's a gap, they'll meet at infinity.

[WilhemHohenzollen]

i mean f(x)=5 when x<-2 so you can't put the point (-2, 5), atleast (-1, 5).
but yeah, you are my teacher Dave.

[beyondartists]

Well detailed explanation. Wasted 3 hr trying to understand my professor 😒

[longlostwraith]

Sorry professor, but I disagree with 2:55 . 0/0 is not undefined, it is indeterminate. Not the same. 0/0 can actually be anything we want, as any real number can be the solution to the equation "0x = 0". Therefore, since "(x-1)/(x-1)" CAN be 1 for all real values including 1, it can be safely simplified without having to exclude 1.

If I'm wrong and you have the time to explain this to me, please do.