Array - 32: Sort array based on frequency of value (If frequency is same then sort based on value)

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Solution:
- Iterate all element of array & put in map (key as number & value as frequency)
- Now map has all value with their frequency
- Now use comparator & compare based on their map value
- If frequency is same then compare using value of array element

Time complexity: O(nlogn)
Space Complexity: O(n)

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Комментарии

how does that comp. understand when we code as freq2-freq1 it has to be descending without knowing which of them is greater?

BACSShaileshShettar

what was that return freq2- freq1 @ 6:16 i'm not quite getting...

godessGOAT

Where is the playlist for array interview questions

mohammedajazquadri

you should put which language you're using in title i.e. C++ / Java / Python

ankitjangir

your code >
input array :{ 10, 7, 10, 11, 10, 7, 6, 5 } ...

output : [10, 10, 10, 7, 7, 5, 6, 11]

11 should not be at the last it should come after 10 .

okfleeaa

Array - 32: Sort array based on frequency of value (If frequency is same then sort based on value)

Array - 32: Sort array based on frequency of value (If frequency is same then sort based on value)

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