Sort array in asc- Interview Python Question

[maxspies]

array = [9, 3, 2, 4, 5, 4]
print(sorted(array, key=lambda x: x[1]))

[banjoller]

array = [1, 4, 6, 3, 6, 4, 6, 9]
n = len(array)
for i in range(0, n):
for j in range(i+1, n):
if(array[i]>array[j]):
temp = array[i]
array[i] = array[j]
array[j] = temp

print(array)

[IQ_reviews]

#Using lambda Functions

Array = [9, 3, 2, 4, 5, 4]
Array.sorted(key=lambda,
Array: Array[1])
Print(Array)

[AhmedMostafa-vn]

Array = [9, 3, 2, 4, 5, 4]
Array.sort(reverse=True)
print(Array)

[sutopajana]

Why are we using i+1? Please explain it

[IQ_reviews]

Array = [9, 3, 2, 4, 5, 4]
Print(list(sorted(Array)))