Java program which intakes 6 numbers as input and prints their average

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public void sixInputAverage() {
System.out.println("enter six numbers one by one to take average of it ");

sc = new Scanner(System.in);
int sum = 0;
System.out.println("enter a number ");
for(int i=1;i<=6;i++) {
System.out.println("enter " +i+" number");
int number = sc.nextInt();
sum += number;
}

System.out.println("average of six numbers are :" +sum/6);
} simple logic

syedarshad
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public void sixInputAverage() {
Scanner sc = new Scanner(System.in);

System.out.println("Enter six numbers one by one:");

int num1 = sc.nextInt();
int num2 = sc.nextInt();
int num3 = sc.nextInt();
int num4 = sc.nextInt();
int num5 = sc.nextInt();
int num6 = sc.nextInt();

double average = (num1 + num2 + num3 + num4 + num5 + num6) / 6.0;

System.out.println("Average of six numbers is: " + average);
}

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