Complex Numbers 03 | Detailed Discussion on Modulus | Class 11 | JEE | Pace Series

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PACE - Class 11th :

Scheduled Syllabus released describing :-
which topics will be taught for how many days.

Duration:-3months (Nov 2020 - Feb 2021)
Free Batch Exclusive on our YouTube Channel:PhysicsWallah-Alakh Pandey

Batch Details

1)Best Faculties across India for different Subject/Topics.
2)Complete & Relevant Syllabus Coverage of Class-11th within 3 Months- Fastrack Nov 20,2020-Feb 20,2021
3)Monday-Sunday : scheduled Classes everyday ( for each Physics, Chemistry,Mthematics & Biology)
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5)Notes Link on Description

Physics:Tues,Wed,Thur,Fri,Sat : 3:00 pm
Chemistry: Physical & Inorganic Chem: Mon,Tue,Wed,Thur,Fri:7:00 pm|| Organic Chemistry:Sat,Sun : 9:00 pm
Mathematics:Wed,Thur,Fri,Sat,Sun: 5:00 pm
Biology:Wed,Thur,Fri,Sat,Sun: 10:00 am

4)Scheduled Syllabus released describing :-
which topics will be taught for how many days.

Lakshya Batch-Complete Physics for Class 12th BOARDS/JEE MAIN/NEET
Yakeen Batch-Complete Fastrack Course(11th & 12th) for NEET
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salute to such a great teacher who recorded lecture 3 times only for us...

AyaanKhan-iyvh
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Best Cinematography award goes to Aman Sir 😊😊

akhil_
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Who is thinking about the deleted video 📷😂😁

manishchoudhary
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sir aap ki mahenat hamare results mein chamke gi.

shivanshrajpoot
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Aman sir, , Alakh sir, , Amit sir, , 😂😂. 🇮🇳🇮🇳 Bhaut Bhari combination

neetdiaries
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Sir ye to dhoka kar diye aap sir lecture number 2nd me question me ( 9z1z2+4z1z3+z1z3) tha aur aab aapne z1z3 ki jagah z2z3 kar diya 😥😥😥

hariomdubey
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Very hardworking persons in physics wallah team...

ramakantyadav
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The solution of homework question is
Let Z=a + ib
So Z conjugate = a-bi
Now Z²=Z conjugate
a² + b²i² + 2aib = a-bi
a² - b² +2aib = a-bi
Now by comparing the real part by real and imaginary part by imaginary
a = a² - b²
b = -2aib
a = -1/2
Putting this in a = a² - b² we get
b = +(√3/2), (-√3/2)
So complex number Z=(-1/2) +(√3/2) i and Z = (-1/2) -(√3/2) i

anjaleegusain
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Sir next chapter PERMUTATIONS AND COMBINATIONS

kevinshah
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If aman sir teaches us mathematics in class 12 in YouTube, then our maths will become purely bhannat !
👇😀😀😀

aseemprasad
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Who knows that, it has uploaded again, after deleted video....

elaborate_aadii
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SIR Jee ke hisaab se Chapter padhaoge naaa mera mtlb ye hai sir agla QUADRATIC chapter hona chahie hai naa jee ke hisaab

mayankbansal
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And the Oscars for best cinematography goes to Mr. Bhannat Aman sir

HemantShivalkar
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Sir 13:11 par Z1.Z2=
(a1a2 - b1b2) + (a1b2 + a2b1)i
Hoga n..
Apne =(a1b2 - b1a2) + (a1b2 + a2b1)i Likha haii..

AmanSingh-ylly
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You recorded this lecture 3 times only for us.
Thank u Aman sir

ManishKumar-cwts
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4:38 SIR MAINE PURA SOLUTION BNA KE PHOTO CLICK KR KE GOOGLE DRIVE PE UPLOAD KR KE LINK COMMENT ME AAPNE HATHO SE DALA THA..ON 26 DECEMBER 08:06 PM BUT STILL YOU ARE SAYING THAT NO ONE UPLOADED THE SOLUTION THIS IS NOT FAIR😕😕😕

himstitute
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last homework question
z²=z'
z=x+0i
z'=x-0i
z²=x²+0i² = x²

x²=x
x= 1, 0
I'm in 10th 😜i hope my answer is correct

classiboy
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Given That:- z^2 =zconjugate

To Find- Possible Solution Of Z
Soln -
(Step1):- write (Z^2 = Z conjugate) in modulus.
:- |Z|^2 = |Z conjugate|
..by Modulus Property ( |Z Conjugate| =|Z|)
therefore,
:- |Z|^2=|Z| ..(equation)

(Step2)by Observing the above equation
| Z | = 0&1

(Case1)-Put |Z|=0
then Z=0 ..Ans.1

(Case2)- Put |Z| =1
then (Z^2)=(Z conjugate) = (Z^-1)..ans.2

Z^3 =1
so, Z =1...ans.3

Therefore, this gives remaining 3 Solution .Hence |Z|^2 =|Z Conjugate| have over all 4 Solutions of 'Z'

❤️PHYSICSWALLAH
❤️PACE
❤️AMANSIR

technicaltanmay
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Ye sir and chemistry wale sir dono twins hn kya..? M confused between two😂😂

swati.k
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PCB students who came for intro and like

randomguy