Find Area of Red Triangle | Geometry Skills

Find the area of the Red Triangle

Given ar 3 squares with sid of 2 units. FInd the area of the right triangle which intersects with the vertices of the square.

[qbz]

There's an easier solution.
1) divide the red triangle with a horizontal line, which is the top edge of the 2x6 rectangle. Call the upper part A.
2) divide A by a vertical line that continues the segment that separates leftmost two squares. we get parts B(left) and C(right).
3) move the part to the right (C) is a 45-degree triangle, which fits the blank space in the third square.
4) rotate the part to the left (B) by 90 degrees clockwise around the left corner.
5) observe that the C forms a 45 degree angle in the middle square, which intersects with the largest diagonal at the center of the middle square.
6) Observe that the remaining blank space is a triangle which has a base of 4 and a third vertex which is located at the center of the middle square.
The total area of the rectangle is 2*6 = 12. The area of the remaining blank triangle is 1*4/2 = 2. The total red area is 12 - 2 = 10.

[harikatragadda]

Can be done using Similar triangles by drawing a perpendicular to the Hypotenuse of the red triangle from the top left corner of the square.

[じーちゃんねる-vn]

((a, a)-(6, 2))･(6, 2)=8a-40=0 a=5 ∴S=(1/2)|(5, 5)X(6, 2)|=(30-10)/2=10

[daddykhalil]

The handwriting is small and the voice is very low.
Too unsuccessful job.

[rey-dqnx]

Angle(45+alpha) wasn’t needed to arrive at the answer. Your going round and round and round which is typical of your past videos. I think you should edit your videos to make it presentable to your viewers. Sorry, this is just a piece of constructive criticism, nothing personal.