Integrate to make trig identities.

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  1. Michael Penn
  2. math
  3. mathematics
  4. number theory
  5. abstract algebra
  6. calculus
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Комментарии
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The fact he didnt multiply both sides by 12 hurts my soul

wynautvideos
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Niceee, that's also 2 functions that have the same graph

davidbarbina
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i feel it's just (sin^2+cos^2-1)^3=0

antonior
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The complex relationship between trigonometric functions can be used as another method
∫(sin(x)×cos(x))³dx
∫(sin(2x)/2)³dx
∫((e^(2xi)-e^(-2xi))/4i)³

-1/64∫(2sin(6x)-6sin(2x))dx
-1/64(-cos(6x)/3+3cos(2x))

MortezaSabzian-dbsl
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This shows the importance of the constant of integration, which is not to be neglected :)

PRABALBAISHYA-xifd
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Yes, it's not practical, but it's just fun to see odd identities.

cameronbigley
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How long does it take to learn calculus, jeez

techno.
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To be honest, the contrived nature of trig identities never belongs on a mathematics exam. I love them, especially in a proof like this, and I love what they can do once the trig identity route is mapped out, but expecting people to know them off the top is wild.

This is coming from someone who had to take way too many quizzes/tests involving the pattern recognition of trig identities.

cd-zwtt
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Should not he have two constants on integration?

jaimeduncan