Projectiles : Above horizontal at a height : Tutorial 2 : ExamSolutions

Tutorial on projectiles that are above the horizontal at their maximum height when projected.

[pinklemonade]

10 years later and these videos are just as useful they’ve helped me so much thank you!!

[ethanroee]

Going through these videos before my a2 maths mechanics exam tomorrow makes a huge difference, you are a legend!

Edit: well it’s four years later or so, what a throwback lol. I did end up passing that exam, went to uni got a first in computer science and just got my first job. How things work out ey. Oh and there’s a bloody pandemic

[ExamSolutions_Maths]

They are standard formulae that you should already be familiar with on constant acceleration. My website has tutorials on these. Just check out the index. Sorry cannot post a link here as YouTube prevents it.

[willlamble]

Thanks alot! i didnt rellay understand projectiles before i saw your videos! cheers.

[arizh]

Thank you so much sir
My classmates and I are so grateful

[EpicEditsBySaz]

I won't be able to see my teacher before Monday, and this video is bang on the nail, thanks! I was a bit confused on what is negative and positive.

[michlleeee]

where did you get all these formulas from? is there a list?

[elliotfryatt]

I’m confused with your rearranging on the max height section. You say to move 2(9.8) to both sides and then divide by 2(9.8). So you want me to divide 2(9.8) by itself?

[ghoda-r]

will the final velocity at the bottom (at -10 displacement) be negative or positive?. using your values ie s=-10, u=8.452, a =-9.81, t= 2.5 i get both positive and negative values for final velocity from different equations. v=u+at gives me a neg ans while v^2=u^2+2as give me a positive??

[ExamSolutions_Maths]

No probs, Hope my site proves useful.

[sharmisthatripathy]

In the 1st video v was -ve but in this video it’s unknown . I am not understanding that part .

[karimmagdy]

i don't understand how the time of flight is calculated as if the particle is projected with horizontal speed only ?? i mean why did you neglect the time it will take to reach the maximum height and add it to the time you calculated ???
thanks

[Dawoodj]

I don't understand why v is unknown, why is it not -20sin25? Please could you get back to me on this. Thank you for your videos btw, they help a lot!

[stephanieokobi]

in the time of flight part, I used the formula for the time of flight and I didn't get the answer you got, why?

[leeparker]

I don't understand how you got the value for t to be 2.5s using h=10m when the total height is 13.6m.

[coldbrewedicecoffee]

how comes the final velocity is unknown and not -20sin25?? Please help

[Xfrome]

Surely for the 'time of flight' part you've only taken into account the time after the particle has gone up, down, and reached 10m above ground once more? What about the initial motion??