Calculus: Integration - Partial Fractions (4 of 16) Case 2: Repeated Linear Factors

In this video I will explain partial fraction Case 2: Repeated Linear Factors.

[valeriereid]

Thanks for another excellent explanation of the application of integration by partial fraction method.

[kristinacossetsolas]

I wish our prof. could teach us like that. so that I will clearly understand :) thanks for that! :)

[ricardofun]

It would be nice if you could come up with some proofs of these techniques, which would provide a good intuition of why it works. I know it's complicated but with your good explanation it would be great.

[prabalbaishya]

Thanks dude your vids really helps me in clearing my concepts.Keep up your great work.

[Volumed]

I definitely learned some new stuff from this playlist... thanks

[MichaelGoldenberg]

You mistakenly wrote the last term with x - 1 in the denominator rather than x + 5. 

[MichelvanBiezen]

Mitchel,
I am not sure what you are asking.  What equation (3) are you referring to?
Since A + 6 = C  implies that   A = C - 6,  you can replace every A in the other two equations with C - 6.
Is that what you are wondering about?
That is a classical approach to solving 3 equations and 3 unknowns.

[karamj]

i solved the last equations with craymers rules, dont hurt me lol. overall fantastic video very great for revision, thank you so much.

[AhmetOmerOzgen]

i gave x=1 before you ve wrote down the lin. eqs. and i found b=3 then after the 3 lin. eqs. things got easier :) :)
thanks for the vids

[lrobertiii]

Hello professor,
Thanks again for your videos. I was wondering about your final answer. Why is it 2 / (x-1) and not 2 / (x+5)? I thought that the 2 corresponds to the C so it would have the denominator that is under C? Is this a mistake or am I wrong?

[Sally-ytuk]

You have just resolved the equation into partial fractions. How about the final answer since the question was all about integration

[SadiqunhnabiChoudhury]

How do you integrate the 3÷(x-1)^2 term? I was waiting for that the whole video

[kentople]

Thanks Sir, it helped with my assignment

[David_CK]

Why expand it as A/x-1+B/(x-1)2 and not A/x-1+B/x+1

[FrostByte_AC]

There's no benefit to taking a test without resources when doing a problem like this when you only had 8 hours to learn it before being evaluated.

[mitchelgatuke]

sir, what happened to the 5A in eq....(3)?

[futurestig]

Why don't we integrate the final results in our solution with A and B