Proof by Contradiction | ExamSolutions

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In this video, we go into depth with negation statements and learn how to do proof by contradiction using 4 simple steps that works every time.

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Big up my guy. Finally been able to understand Proof by Contradiction after months of struggling with it. Will definitely be using the NACC method from now on. Cheers man, keep the vids coming!!!

joshuafrancis

This has been do helpful!!!! You totally saved my college algebra grade. Keep up the great work

gaara

Thank you, this is the video I was waiting for

AshVentureOfficial

I thought this was a really good explanation. Great video 👌🏽
Can you please try to make the audio consistent and less "echoey"? It's not a big deal but would definitely make a positive difference! The audio was best for a couple of short periods at the beginning of the video.

The last proof was really cool but at the same time intimidating...left to my own devices, I don't think I would have been able to complete step 3.

hrperformance

Thank you so much for this amazing explanation really appreciate it

Funnyvidslaughter

I have a question like why we are assuming a/b in it’s simplest form ?

esha

The correct breakdown should of been. U square both sides and then multiply throughout by b²

markmohammed

But why do we assume that a/b is in simplest form why not any form is it because that any fraction can be simplified ?

aashsyed

11:17 can someone please explain to me why if the square root of 2 is rational 2 = a/b many thanks

souppp-nhwf

b × Square root of 2 = b sqare root 2 . Not square root of 2b.

markmohammed

how are we proving n^2 and n both being even by assuming n to be odd and finding n^2 to be odd? disproving the assumption does not prove the original statement what so ever
the assumption was not matched either if we proved the assumption wrong then it would have made sense

faheemiqbal

I was expecting an explanation after every move

bolatagane_tukss

there is no God " but God "
there is no God (statement)
but only one true God (negation)

mandarkm

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