Prove 1+sec⁡ A/sec ⁡A = sin^2 A/(1-cos A) | Exercise 8.4 Q5 part (iv)

Exercise 8.4 question 5 part (iv) class 10

Prove:
(1+sec⁡A)/sec⁡ A = (sin^2 A)/(1-cos A)
Or
1 plus sec A upon sec A = sin square A upon 1 minus cos A

Strategy🧠:
Express sec in terms of cos A
Simplify RHS and LHS respectively.

Hint 💡
Trigonometric identity:
cos2 A + sin2 A = 1
1 + tan2 A = sec2 A
cot2 A + 1 = cosec2A

Algebraic Identity
(a+b)^2 = a^2 + b^2 + 2ab
(a+b)^3 = (a+b)(a^2 -ab + b^2)
a^2 - b^2 = (a-b)(a+b)

Note📝
The above question is taken from NCERT book ch-8 exercise 8.4 question 5 part 1 Trigonometry.
Read it 📖
Identity:
An equation is called an identity when it is true for all values of the variables involved in it.

Trigonometric identity :
Similarly, an equation involving trigonometric ratios of an angle is called a trigonometric identity, if it is true for all values of the angle(s) involved.

Practice👩‍🏫:
Can you solve it 👇
tanθ/(1-cotθ)+cotθ/(1-tanθ)=1+secθ cosecθ

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[vidhikumari]

Or bhi difficult method se karbati madam

[imamagicalarmyblink]

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I got confused in this sum thank u for explaining this sum clearly mam

[vidhikumari]

Or bhi difficult method se karbati madam