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Prove That (1+Sec A)/(sec A)=(sin^2 A)/(1-cos A)
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Prove That (1+Sec A)/(sec A)=(sin^2 A)/(1-cos A)
Prove That (1+Sec A)/(sec A)=(sin^2 A)/(1-cos A)
Prove 1+sec A/sec A = sin^2 A/(1-cos A) | Exercise 8.4 Q5 part (iv)
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1 + secA / secA = sin square A / 1 - cosA. INTRODUCTION TO TRIGONOMETRY
Prove that : ` (1-sin A)/(1+sin A) = (sec A - tan A)^2`
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`(1-sin^2theta)sec^2theta=1`
sintheta-costheta+1/sintheta+costheta-1=1/sec theta-tan theta
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CosA/1+SinA+1+SinA/CosA=2 SecA
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Class 10 Maths (Trigonometry) Example-15, Ncert, Using the identity sec^2 theta = 1+ tan^2 theta
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