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Prove that 1+seca/seca=sin2a/1-cosa
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Prove that 1+seca/seca= sin2a /1-cosa. From LHS to RHS directly How to prove. 1+seca/seca=sin2a/1-cosa,
prove 1+seca/seca=sin2a/1-cosa,
seca-1/seca+1=sin2a/(1+cosa)2,
1+cota/seca=sin2a/1-cosa,
1+seca/seca=sin^2a/1-cosa,
1+seca÷seca=sin2a÷1-cosa,
prove that 1+seca/seca=sin2a/1-cosa,
1+seca/seca=sina/1-cosa,
1+seca/seca=sin^a/1-cosa,
1+seca/seca.
prove 1+seca/seca=sin2a/1-cosa,
seca-1/seca+1=sin2a/(1+cosa)2,
1+cota/seca=sin2a/1-cosa,
1+seca/seca=sin^2a/1-cosa,
1+seca÷seca=sin2a÷1-cosa,
prove that 1+seca/seca=sin2a/1-cosa,
1+seca/seca=sina/1-cosa,
1+seca/seca=sin^a/1-cosa,
1+seca/seca.
Prove that 1+seca/seca=sin2a/1-cosa
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prove that 1+seca/seca=sin2a/1-cosa
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