Show that: `1/(sec A-tan A) - 1/(cos A) = 1/(cos A) - 1/(sec A + tan A)`

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Show that: `1/(sec A-tan A) - 1/(cos A) = 1/(cos A) - 1/(sec A + tan A)`
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Комментарии
Автор

Bhai multiply krne ki jarurat nhi thi simply identity laga skte the aage 😮

axgaming
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Its could be more ez if u take that 1 as (sec²A-tan²A )/secA -tanA -secA
Then, it will be
SecA+tanA- secA

unknown-thrl
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Samghana nhi aata na to video mat banaye kre

KushagraSrivastava-gcmx
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Kuch smja nhi pa rhe ho ita jaldi h to video hi mt banao

aloneakshat
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Sir, I have a better one
1/(sec A - tan A) - 1/cos A = 1/cos A - 1/(sec A + tan A)
LHS = sec A + tan A - sec A
= sec A - (sec A - tan A)
= 1/cos A - 1/(sec A + tan A) = RHS
then why to prove like this ??

shivanshsinghrana