[Discrete Mathematics] Set Operations Examples #2

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In this video we do some examples with set operations. For instance, given some operators, can we find the original sets? We also do a proof with subsets.

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It comes with video lectures, text lectures, practice problems, solutions, and a practice final exam!

Trevtutor
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Omg, I can't believe I'm starting to get all of this. I think I'll just go over the whole set theory videos to really cement all the knowledge.

cristicode
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Awesome videos. Maybe its just me, but for my discrete math course they ask for rules to be explained as well when it comes to proofs like you showed around 6 min~. Stuff like associativity, commutativity, universal specification, demorgans, etc. Itd be really helpful to have those added in for a future iteration of this video if you end up going that route. It would just make things click better and feel more complete.

Thank you again for these videos, you are the gold standard for discrete math videos on youtube from what I’ve heard on the interwebs! Congratulations

TepesEdi
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i love your videos :)
in about 23 hours i have learned way better than the whole semester
my only wondering will be if i'm watching [Discrete math 1] playlist, why is youtube suggesting it to me in every video of this playlist?

A.I.Office
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I guess you must add an extra videos in every topic to explain the importance of discrete mathematics there and its possible applications in reality. Overall, your educational style is perfect and very amusing

HAAH
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Thank you so much sir. I really love the way you explained one by one. Finally i can understand this subject better than before

muhammadsyauqiabdulghani
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You're a very good teacher. I was able to do a lot these before watching the explanation. However the proofs are a bit challenging..Thanks!

Retardsbeeverywhereb
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B-A IS correct guys (2, 6)


becase B= [1, 6)= { 1, 2, 3, 4, 5} ; A=[0, 2]={0, 1, 2} so B-A IS ALL num in B AND not in A = {3, 4, 5} of you can write it also as (2, 6) not included 2 and 6 that is why you have (, )

moucharibe
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First off, I appreciate your videos, they are great! Question about your proofs at the end, though (6:50).

Your logic is certainly sound about proving that x is an element of both A intersect C and B intersect D. But how is that sufficient evidence to prove that A intersect C is a SUBSET of B intersect D? Though it may be intuitively obvious in this case, how would you show that it isn't the other way around, that B intersect D is a subset of A intersect C? The way I see it right now, the argument just states that x is an element of both sets, but doesn't really demonstrate which set is the subset.

EDIT: My guess for that part of the proof would be to prove that there exists a y that is an element of B intersect D that is not an element of A intersect C. This means that B intersect D could not be a subset of A intersect C, leaving the only option that A intersect C is, in fact, the subset.

khchosen
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After spending some time with A\B or yours A-B I understood trhat it can be seen as "inside A but not inside B" or reverse B\A, B-A as "Inside B but not inside A"

EeizeMode
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I SAW some people get confused about B-A don`t forget B=[1, 6) So you can not include 6

moucharibe
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I am watching this series in a playlist, you didn't cover the {1, 6) I thought it was {1}, {2}, {3}, {4}, {5}.
If you covered it before do you know where?

aame
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Really great video my friend! I liked the proofs a lot.

Nobody-Nowhere-Nothing
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thank you for this video this help me a lot of bit for my course

ariannesumayop
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hey great video it helped a lot!!
However I'm still a bit confused on the first proof. As B and D are not subsets of A and C respectively, could it not occur that the intersection of B and D contains elements that are neither in A or C ? Is A intersection C still a subset of B intersection D in that case?

aliceamanatidou
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Typo on the title. Other than that, great video man!

PieroVera
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5:54
If A doesn't have members that are also members of C then how can the intersect?
That proof doesn't always work. Unless you assume that A and C have an intersect or if you remember that the empty set is a member of all sets? Am I right?

anteconfig
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I'm so confused about the proving questions, are we actually just trying to prove that these equations are possible? How much assumption are we suppose to make? Why do we make only one here? Or can I make enough assumptions to make it possible every time?

sunnyiong
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Having some trouble with whether or not a set can intersect with its powerset

vidro
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If you can explain the B-A in more detail, I'd appreciate it. Everything else is good.

justinkelley