Solving An Exponential System #maths #algebra #exam #sybermath

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[GrindelTF]

i was going with the log method bit this so much better
rlly cool

[AyushRay-gf]

I did in a different way
2^x=27
2^x=3^3
Ln(2^x)=Ln(3^3)
X×ln2=3ln3
X=3ln3/ln2
Similar y=4ln3/ln2
X+y= 7ln3/ln2
X-y=-ln3/ln2

Dividing them we get -7😊

[kbin]

My sol:

2^(x+y) = 27*81 = 3^7
x+y =4 log2(3)

2^(x-y) = 27/81 = 3^(-1)
x-y = -log2(3)

x+y/x-y = 4log2(3)/-log2(3) = -7