Solving equations with lambert w function #shorts

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Комментарии
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it feels like the Lambert w function is a pretty useful exercise for spotting invisible things that will lead to solutions. The math is crazy, and this skill is not something humans are designed for.

In schools teachers can't present information and in college they expect you to be a genius and get everything straightaway without any practicing

cmcumm
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There's no explanation as to why the given solution is helpful/useful for anything though.

MsHojat
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Thanks for NOTHING! That explanation says nothing about what exact # will solve the equation.

StevenTorrey
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Why is it +4 and not -4 if we moved 4 to the left

kami
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a^x + x = b
x = b - [w(a^b • lna)]/lna

2^x + x = 4
So x = 4 - [w(2^4 • ln2)]/ln2
= 4 - [w(16ln2)]/ln2

cosmolbfu
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It seems like the exponent needs to match the added x term to work out. I made a gen solution doing the same process.

AB^(Cx^n) + Cx^n = D

x^n = [-W(AB^D * lnB)/lnB + D] / C

If there’s a way to do it where they don’t need to match as Cx^n, what is it?

darcash
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This is tantamount to nonsense, let take an equation that you can easily solved using numerical method fanny around with it to get it define in terms of a function you can determine using numerical methods.

cupidstunt
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I don't have a clue what that whole explanation is. What i do know is: 2X+X=3X. So so X is 1.66667 in my head

MarkGlowInTheDark