A-Level Maths: L1-08 [Data: Histogram Problem]

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what an absolute king
appreciate you for your amazing teaching and the effort you put into making these videos

yasar
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Hi there,

Can you please make a video on how to tackle those questions about the heights and widths of the bars?

numaira
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Hi there,

I'm a little bit confused, with the value of 8, I used the formula and got k = 1/8.
The text book formula:
area of bar = k x frequency
We're told that the frequency is 96 and we calculated the area to be 12, so after substituting those values in I got
12 = k x 96, so k = 12/96, k = 1/8.

So firstly, have I calculated the value of k correctly? Secondly, to calculate the frequency that each bar represents, would I simply need to substitute k = 1/8 and the area of each bar into the equation? Thanks in advance.

rahimahmed
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Ocr mei seem to neglect the proportionality aspect saying that frequency density multiplied by class width is equal to the frequency in their textbook.

diongeorge
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Thanks sir
Only 15 hours left to my statistics exam

Real_Madrid.
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For part C, could you use the formula, median = lower bound + (number into class/total number in class)*class width. In this case, you would get: 20+(24/96)*10 =22.5. Just wondering because your method may be more useful in more complicated examples?

jamminermit
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hello sir, why is a=kf, and ka is still equal to f. For example why isn't the first band just 5*0.6 as the frequency. Thanks in advanced!

kngzlyv
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Do you now if there's questions available out there so I can practise them

steffananother
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Hello, is Part C called linear interpolation and is it on the AQA specification?

mellowhead
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If you know the 20-30 class has a frequency of 96 and therefore when k=1 the frequency density would be 96/10 = 9.6, why would you then choose to have a y-axis that would claim the frequency density is 1.2? You could have exactly the same histogram with exactly the same size and shape bars, exactly the same class widths, each bar with exactly the same height as you currently have - nothing would change - and just label the y-axis 'correctly'. So what purpose does it serve to divide all the frequency densities by 8?

gattocattivo
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Can I do 10 x 1.2 = 12
then use the formula area = kf
so k = area/f
k = 12/96 = 1/8
then use
f = area /k
f = 18/1/8 = 144?

Alen
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DO I NEED LINEAR INTERPOLATION FOR OCR AS MATHS ? :)

JK-vmyo
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Why did we not use a table with the cumulative frequency like in the previous videos? Is it because k is not equal to 1 here?

badyahelamin
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How are you meant to know when to use n/2 or n+1/2 for the median. I've done a few questions but the mark schemes each use the different methods. I feel like there's some obvious rule to follow but idk?

mk_
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Why isn't it 216-144 instead of 216-120? Thanks

miawalker
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how can the number of people be continous data?

metekuner
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hi so in part A you've done Area=10x12=12 but like it doesn't you know
help

kevinmushtaq
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I thought frequency was class width X frequency density[ for question B.

gateway