Evaluate Sum of Series with Sigma Notation Higher Lower Limit

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[ZE.basic]

Thank you, Mr. Anil Kumar you're a life savior!

[sajedaahmed]

Preparing for a scholarship-qualifying exam, thanks that helped.

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[gone]

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[adrianoshonoshonos]

Thank you so much for this very helpful tutorial, Sir. I appreciate it so much and it made me understand our lessons x10 better! Thank you! May God bless you

[scienceproject]

BRO THAT'S FREAKING GENIUS THANK YOU SO

[nayd]

taking introduction to computer algorithms for my final university year and this explained it 1000x better than the textbook

[mahaelsiah]

thank you so much the only video that truly taught me sigma

[LaLaLa-dhsf]

Thank you so much! I am really thankful

[zia-i]

i=10
Un=29
so theres 20n
the firs n=3(10)-10=20
the last n=3(29)-10=87-10=77
Sum= n/2(first n + last n)
Sum= 20/2 (20+77)
Sum=10(97)=970
Is mine easier?

[reignhard]

Thank you so much Sir ☕ don't forget to drink water, everyone!

[lucyheartfilia]

I don't understand how did you get 9 for the upper limit.. Please reply I have an exam on Monday

[ThePrettyFLMan]

So for this one problem I am doing my upper limit is n= 7, and the lower limit is i= 4. So for the first one outside the brackets, do I make sigma n=7 and i=1, and the brackets inside n=3 and i=1?

[jerredanugot]

I think you've made a small mistake. -9(10) is -90, so 1305-290-135-90= 790. Furthermore, you really did a great job on enlightening about the i, thanks.

[Lolsade]

What if the lower limit or i is zero? Does it change the process? Keep up the good work

[mofeiyang]

if u r able to use a scientifical calc in a math test, just plug in all the sigma stuff and block out more time

[ilobeducks]

does someone know what to do if my upper limit is n?

[adarshaindia]

Sir, it could have been way simpler 3(10+11+12+13+....29)-(10×20)
={3×(20/2)×(10+29)}-200
=(3×10×39)-200
=1170-200
=970.