Square, Semicircle, Quarter circle

[alexismiller]

best way to solve the problem before looking at the solution is to do it at half past midnight, blurry-eyed, laying in bed looking at phone, trying to do the algebra in head
10/10 experience

[TheChaoticDerp]

Nice! I ended up using trig. to find the angle of the triangle made by the centerline between the centers of the circles, which results in having to solve "cos(x) - sin(x) = -1/3, " which requires you to use the Harmonic Addition Theorem to solve and results in a really messy answer. The "a" of the square is then "(5+10)*sin(x), " and you can solve from there. The method you used is a really neat way to attack the problem, and I wish I'd seen it on first glance!

[eckhardfriauf]

So glad that I have discovered your channel.

[Waldlaeufer]

A wonderful additional question would be: What is the length of the tangent line through the point of contact of the two circles bounded by the square?

[belalabusultan]

sounds like middle school math problems, I wouldv'e needed to look for the exact equations/laws, but I had the general idea of how to solve it.

[vojtastruhar]

Its annoying because it isn't made obvious that the common point of the two white areas also lies on the connection of the two "middle points" od the white areas. That is a crucial information. Sigh.
Good job man! Nicely explained

[flatlne]

У тебя крутые видосы мужик, продолжай в том же духе!

[raminkadkhodayi]

Nice chanel but very low view, good luck bro

[JT-uxjb]

I'm confused how you get a squared, after using quadratic formula...

[mrbartinio]

Anyone else saw dream's profile pic?

[jerry]

A bit more tricky if you aren’t given that it’s a square

[BaieDesBaies]

Ho do you know both radius are colinear ?

[Mr.Slinky]

I thought it would be super easy but then realised I didn’t have a side length, so it took a bit longer than expected