Physics CH 0: General Introduction (19 of 20) Basic Trig for Physics - The Triangle (Cosine)

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In this video I find the 90 degree distance to the tension cable.

Next video in the series can be seen at:
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Hi professor! Just had an interesting geometrical question for this problem. I remember from video (17 of 20), you said that in any right triangle, the two non-90° angles θ + Φ always = 90°. So say in this problem, we call the unlabeled angle in the diagram "phi" Φ. Could we technically solve for this new angle by saying cos(90° - Φ) = d / L and then rearrange to say that Φ = -cos^-1(d / L) + 90° ? Thank you!

robertonoz