Proof that sum(sin(n)/n) Converges using Dirichlet's Test

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Proof that sum(sin(n)/n) Converges using Dirichlet's Test
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You give the best proofs. I can’t understand really anyone else doing these proofs. However when I watch your proofs I can understand it. You actually break it down and explain stuff . Thank you !

joshual
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Thanks profe! It filled all the gaps in my textbook.

josesilesramirez
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Thank you very much for this beautiful explanation. I have a midterm exam today. It will definitely work for me. Greetings from Turkey 👋

Lt_McQueen
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Can't we actually use the fact that sine bounces from -1 to 1 to actually show that bn is bounded?

matthewluna
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Non conoscevo il test di dirichlet... Complimenti

giuseppemalaguti
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Nah bruh I ain't wanna go to kindergarten no more, this shit lookin hard af 💀💀

Theconhead
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How can you show the series sin(n) /n is not absolutely convergent?

sumittete
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Starting from | sum_n=1 to N e^(in)| and using the geometric series would be much easier.

FunctionalIntegral
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Have you proved this using conditional convergence if so can u send the link

mohammedafzal
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please help me what about sum (ABS(sin n))/n

Patate_douce
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(Sinn)/n>-1/n
Since summation -1/n divergent series...
Thus by comparison (Sinn)/n divergent 🥲🥲 where I m wrong plzzz explain....

AkashKumar-plnu
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Sorry Mr, are you sure? because i think that sum is diverge
what do you say?

abdelazizbaadji
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Sir is this absolutely convergent? Or conditionally convergent

amritawasthi