The Sequence a_n = sin(n)/n Converges or Diverges Two Solutions with Proof

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The Sequence a_n = sin(n)/n Converges or Diverges Two Solutions with Proof

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Hi, I was looking at this video for the convergence of the sin n/ n series, You have used the negation of the Divergence test to prove that this seq is converging. But according to the theorem if a_n conv implies lim n-> infinity a_n = 0. You can't say that if the limit is zero then the seq converges.
Please correct me if I was wrong.

joelsathiyendra

Word of warning, I'm fairly confident this math is not sound. You declare here that the limit of An = 0, which is not enough to declare this function convergent or divergent. For example the limit of 1/n = 0, but it's a divergent sequence.

karamkhanna

Here we call squeeze theorem as sandwich theorem

palakshpatel

Some teachers uploaded his vedeo on goggle with dollars to seeing the vedeo this is very bad in my mind bcoz students have no enough of Money

MuhammadHafeez-mgmj

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