Integration by partial fractions - repeated linear factors

In this video, Professor Gonzalinajec demonstrates the technique of partial fraction decomposition for use in integration.

[mikotansingco]

Because the denominator is (x-2)^2, let u=x-2, u+1=x+1, du=dx, giving us ((u+1)/(u^2))du. Solving it this way removes the need to use partial fractions.

[LUSHARKBOY]

Y can't you go directly to the calculation