Differential Equations | Two quick applications of convolution.

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We present two quick applications of convolution, both involving integrals.

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Excellent work man, but you did a mistake applying the Laplace transform to (t), it is 1/s^2, hence y(t)=sin(t)

joanmartinsuarezloaiza
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man I gotta learn that partial fractions trick...

zakatk
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Your explanation of what happens when one differentiates on the left misses the t under the integral sign. Not that it helps.

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