Projectile motion #vigyanrecharge

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[pEpE-pxuz]

The position of the object at T/2 time where T is the time of the projectile motion, will be the position where vertical velocity will become zero or simply VSin∅*T/2 - 0.5g(T/2)² where V is the initial velocity and ∅ is the angle of projection

[ujjawalpathak]

maximum height pr kyuki waha pr gravity ke dwara applied velocity ki value vertical velocity ke brabar ho jati h aur vo ek dusre ko cancel out kr dete h.

[sanidhyadwivedi]

T= U sin theta / g
U = initial velocity
g = acceleration due to gravity 😊

[rudrapandey]

To get Max range the object should be projected at 45⁰

[anonymous_milion]

😁😁 सर जी जैसा विडियो में दिखाया गया है क्या सच में ऐसा संभव है

[devtakhilan]

90° from horizontal.
At maximum distance (vertically) velocity is 0.⬆️ Hold(0 velocity) ⬇️

[abhishek]

At h max vertical velocity will be 0

Where, h max = highest point where a projectile can be reached

[TechnoFacts]

The title must be... Pov: When science defeated common sense

[iamfromvillage]

Bahubali : muze physics nahi padhani😊😊
Katappa : 👿🗡🗡⚔️

[jtshort]

Maximum hight or time t/2 or range r/2 pe u sin theta 0 hogi..
Because maximum hight pe angle sin ke lie 0 hota am a genius.

[SamarKhan-bodd]

Maximum height velocity along vertical is zero but not horizontal because for horizontal g is constant through motion ❤

[DebrupSamajpati]

Vertical velocity will be zero and horizontal velocity will be min at the topmost point of projectile motion. So we can say at the topmost point of projectile, Vel is min but it will not be zero.

[A_Boy_From_Mars]

Kal hi rajwant sir ne padhya tha 😅

At max height it will have 0 vertical velocity while horizontal velocity will not change throughout the motion

Abb like thoko 👍

[biologybaba]

जब बाहुबली को 0 डिग्री के कोण से फेका जाए तो उसका लंबवत गति 0 हो जायेगी।😂

[VikrantAnand-zsyr]

On top position 😢😢😢
If right then please like 🤗🤗🤗🤗🤗

[pwkastudent]

At max height the particle will have horizontal velocity and no vertical velocity and horizontal velocity=ucos theta

[Youxr___sahil]

Sir salam hai ap ki mainat ko jo ap ke 4 hour non stop padaya hai 🎉🎉🎉🎉

[vey]

Sir vertical velocity 0(zero)= *vsin0°*maximum height be hogi or but horizontal *vcos0°* hogi or fir uske bad gravity 10(9.8 ) m/s² lagega

[AdityaYadav-czc]

T=UsinQ/g
T=time
U=initial velocity
g=accleration due to gravity
Q=angle
Sin = vertical projection

[roxx]

Maximum Height pr
Kyuki g apply hoga object pr