PreCalculus - Trigonometry: Trig Identities (50.5 of 57) Solve cos(x)sin(x)-2cos(x)=0, x=?

This video is an error-free video of "Trig Identities (50 of 57)". The video with the error is located at:

In this video I will solve cos(theta)sin(theta)-2cos(theta)=0, theta=?

[إيادالشايع-جر]

Greetings
I would like to point out that you made a mistake in factoring the cos. It should be cos(sin-2)=0.
However, I like to thank you for the effort that you make, and keep going my friend.

[alexluthorkos]

Sir, here the solution 45 degrees is valid if you check on cos(theta)^2 instead 2cos(theta).I love your videos, thank you so much!!!

[WolfgangBernady]

You successfully solved a different equation. Maybe change the title and description? (to minimize effort?)

[Muffin--Man]

θ ∈[0, 2 π]
For : cos(θ)*(sin(θ)-2)=0, cos(θ)=0 θ0=π/2, θ1=3/2π [cos (θ) symmetrical to the x axis, sin (θ) symmetrical to the y axis(see unit circle)], sin(θ)=2 no solution.
For: cos(θ)( sin (θ)- cos (θ))=0, cos(θ)=0 θ0=π/2, θ1=3/2π ; sin (θ)= cos (θ), θ2= π/4, θ3= 5/4π

[jacobsabata]

can theta = 3(pi)/2 be another solution to cos(theta) = 0?

[muntaseralabdulla]

he is right but anyway thanks for your videos sir