Basics of Network Theory (Solved Problem 6)

Network Theory: Basics of Network Theory (Solved Problem 6)
Topics discussed:
1) The solution of GATE-2000 (ECE) Network Theory problem on Kirchhoff's Voltage Law (KVL).
2) GATE-1999 (EE) Network Theory problem on Electric Power as the homework problem.

Music:
Axol x Alex Skrindo - You [NCS Release]

#NetworkTheoryByNeso

[surajkantsharma]

(B) is the correct answer.
For case P=18w, as we know that P in case of current is equal to I^2.R, so I^2R= equation
Case 2
V=I
Power in terms of voltage is equal to V^2/R
So V^2/R= 4.5w (2) equation
As V =I so equation 2 will be
I^2/R=4.5
I^2=4.5R put this value in equation 1
4.5R.R=18 from here we get R=2ohm
Put R=2 in any equation we will get I=3A

[pius]

Sir when will you complete this series?

[KajalSingh-xgjp]

Correct Ans --> (B) 3 A, 2 ohm

Explanation:

P1 = (I^2)*R = 18 => R = 18/(I^2) --- equation (1)
P2 = (V^2)/R = 4.5 => R = (V^2)/4.5 --- equation (2)

It is given that magnitude of V and I are same.
--> let, V = I = X

So, R = 18/(X^2) = (X^2)/4.5 --> 18*4.5 = (x^2)*(X^2) --> 81 = (X^4)
we get, X = 3

Hence, I = X = 3 A

Now, R = 18/(I^2) = 18/(3^2) = 18/9 = 2 ohms

[divyarao]

Some one please provide the detailed solution

[avunooritagore]

I'm getting all options. But which is is correct I don't know please give solution for Thia question sir.

[sachinkotagond]

trick - Get the answer from the given options !!! :-D

[Shoron]

Sir i'm 2nd year student. I know all this . But,
I have to see again.
Will you please tell me when the series will complete?

Then i will see all the episodes.