Basics of Network Theory (Solved Problem 9)

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Network Theory: Basics of Network Theory (Solved Problem 9)
Theory discussed:
1) Solution of GATE-2003 (ECE) Network Theory problem on number of equations required to solve any network.
2) GATE-2002 (EE) Network Theory problem on calculation of equivalent resistance using the symmetry as the homework problem.

Music:
Axol x Alex Skrindo - You [NCS Release]

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Sir after each homework problem, pls provide the answer in the next video lecture so that we can cross verify...

NaveenSword

correct answer is 45/33=1.3636V, simplest solution is using 2x delta wye conversion with 'a' and 'b' node and then using 'extended' symmetry, then current from node 'a' is split into 7/11A and 4/11A.

lanride

name the other nodes as cdef

for c node to reach a node : 1 branch
for c node to reach b node : 2 branch

for d node to reach a node 2 branch
for d node to reach b node 1 branch

for e node to reach a node 1 branch
for e node to reach b node :2 branch

for f node to reach a node :
2 branch
for f node to reach b node 1 branch

therefore c and e are equipotential
and d and f are equiotential

therefore every branch that comes between c node and e node will be shorted (here only diagonal branch gets shorted)
therefore every branch that comes between d node and f node will be shorted (here only diagonal branch gets shorted)

so at last we have
1 ohm parallel to 1 ohm = 1/2
1 ohm parallel to 1 ohm parallel to 1 ohm =1/3
1 ohm parallel to 1 ohm = 1/2

and now they all are in series = 1/2+1/3+1/2=4/3 ohms
V=IR=1*4/3=4/3VOLTS

THANKS ME LATER

sabiyanaikwadi

If you model the circuit with software, you will find the _exact_ answer to be 1.363636. This answer can be obtained by conducting two successive delta-wye conversions. The first conversion collapses two triangles to leave two remaining triangles with one common side (after adding the two legs with two series resistors). The common side is 1 ohm, the other sides are 1/3, 4/3, 1/3, 4/3, and the resistors sticking out from the triangle tips are 1/3. Then you conduct another delta-wye conversion on one of these new triangles. After adding the series resistors, you are left with 1/2 ohm and 1/3 ohm resistors on either side of a square comprised of a parallel combination of 5/6 and 35/24 ohm. This will give you 1.36363636. Model the circuit and this is the number you get.

bomberman

1.36... or 15/11 By star delta (exact right ans)
Or
1.33 or 4/5 by equi potential (similar ans)
This because when we use equi potential method we assume that the nodes are have same potential but that's not true hear because some small amount of current flow between them.

alloc

Sir I have a doubt. This circuit is non-planar right? (Branch 4 overlaps branch 3), then how can we apply mesh for this circuit? Pls someone clarify

Surya-qkik

Correct ans is Vab= 2/3V=1.5V
Solve by using delta to star also u can solve by finding symmetry of wheat stone bridge
No current will flow from the middle resistors

vaishnavipatil

R equivalent=4/3 ohms
V=IR=1*4/3=4/3v

akhilasadhula-ftec

point c, d and e, f are equipotential points (as consider L to R ) ans is coming 4/3 volt.

jitendrasingh-eygr

1.36v correct answer solve by using delta to y network conversion

ramakrishnatejapanthagani

in homwork problem
1 use bridge concept
2 use symmetry about vertical

then we get 4/3
why we don, t use bridge in two times because observe carefully in 2nd time bridge condition is not satisfy so here we use symmetry

artisharma

4/3 volts
by redrawing the circuit using equipotential points

rajeeshratna

Calculate the equivalent resistance between a and b using Delta to why = 1.36 ohm v=I*R =1*1.36=1.36v

reficeismail

4/3....equ potential lord...this was interesting

k_EC_ANURAGPAL

BY USING EQ POTENTIAL POINTS 4/3 IS MY ANS. TELL ME IT'S CORRECT OR NOT (tried delta to wye also but its getting more and more complicated)

rahuldahare