Calculus 3: Partial Derivative (14 of 30) Find More Partial Derivatives: Example (2 of 2)

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In this video I will find the 1st and 2nd partial derivative with-respect-to x and y of f(x,y)=(x^2+y^3)^(1/2).

Next video in the series can be seen at:

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Can't thank you enough for this. This is a similar problem to the one in my Larson book section 13.6 #9

Capitan_Chaos

Thankyou very much professor Van Biezan! You are the best.

shaneaipa

thanks Professor Van Biezan! you are the best!

faizandarsot

@1:30 Is the quotient rule necessary? Since we treat x as a constant when taking the partial derivative with respect to y, I merely multiplied the numerator x, by the derivative of the denominator. So...

Partial derivative of (x)*[(x^2+y^3)^-1/2] with respect to y becomes:

Rewrite:

...which becomes:

-3x(y^2) / ((x^2+y^3)^(3/2))

...which is the same answer as you got in the video.

ssrrapper

Sir, the equality of Fxy(0, 0)and Fyx (0, 0) of the function f(x, y ) =[root over (x2 +y2)] sin2@

surjapurilarka

hey..! i was good at maths but now i am not getting it ln calculus any advise unlike

but if we should practice then tell me how to practice
and how to manage other subjects as well
please

hooriakhan

If it was sqrt(x^2 + y^2), could I do it using polar coordinates?😯

nilsoncampos

Walker Cynthia Lee Elizabeth Young Kimberly

FannyMag

You are like my teacher, this videos is not for you explain it better.

forcommentpurposes

Professor, isn't the derivative of x equal to 1, not 0?

dhanushkakonara

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